A car whose mass is 2 metric tons is accelerated uniformly from standstill to 1000 kmph in 5 seconds. What is the mass, acceleration, and the driving force in Newton's? - Quora
![SOLVED: Use g = 9.8 k9 tanker of 6,000 metric tons (1 ton =1000 kg) into the harbor char tugboats = are pulling Two exerts force of exerts force of magnitude 750 SOLVED: Use g = 9.8 k9 tanker of 6,000 metric tons (1 ton =1000 kg) into the harbor char tugboats = are pulling Two exerts force of exerts force of magnitude 750](https://cdn.numerade.com/ask_images/f7c9c2d30b744654989a68d5ad5d5dc9.jpg)
SOLVED: Use g = 9.8 k9 tanker of 6,000 metric tons (1 ton =1000 kg) into the harbor char tugboats = are pulling Two exerts force of exerts force of magnitude 750
![A car of mass one metric ton accelerate from rest at the rate of 2 m/s^2 from t = 0 sec to t = 10 sec . There after it travels with A car of mass one metric ton accelerate from rest at the rate of 2 m/s^2 from t = 0 sec to t = 10 sec . There after it travels with](https://haygot.s3.amazonaws.com/questions/1985644_1297849_ans_5966d7b54ea74933be230c17e1dc8a28.jpeg)
A car of mass one metric ton accelerate from rest at the rate of 2 m/s^2 from t = 0 sec to t = 10 sec . There after it travels with
A 10 metric ton truck drives up a hilly road of inclination 45^° at a speed of 36 km h–1. If the coefficient of kinetic friction between the road and tyres is
![Kitielal V S on Twitter: "#neet #jeemains A #cart has #mass 2 metric ton and sand of 1 metric ton is inside the cart. Now a force of 10 N is applied Kitielal V S on Twitter: "#neet #jeemains A #cart has #mass 2 metric ton and sand of 1 metric ton is inside the cart. Now a force of 10 N is applied](https://pbs.twimg.com/media/EZ-cq2IU8AIThpW.jpg:large)
Kitielal V S on Twitter: "#neet #jeemains A #cart has #mass 2 metric ton and sand of 1 metric ton is inside the cart. Now a force of 10 N is applied
![A text-book of electrical engineering;. 450 3-18.10* 14-6 20 490 3-46.106 21-3 25 505 3-56.106 Motor 27-3 la £ = 500 - 2-75 . 7„ r.p.m. = 3-18.106.1 5 486-2 970 A text-book of electrical engineering;. 450 3-18.10* 14-6 20 490 3-46.106 21-3 25 505 3-56.106 Motor 27-3 la £ = 500 - 2-75 . 7„ r.p.m. = 3-18.106.1 5 486-2 970](https://c8.alamy.com/comp/2CENHMY/a-text-book-of-electrical-engineering-450-3-1810-14-6-20-490-3-46106-21-3-25-505-3-56106-motor-27-3-la-=-500-2-75-7-rpm-=-3-181061-5-486-2-970-10-472-5-590-15-4587-460-20-445-410-25-431-2-390-220-electrical-engineenng-by-means-of-these-figures-we-candetermine-the-speed-at-which-a-tramcarof-given-weight-will-ascend-a-given-incline-as-well-as-the-current-taken-indoing-so-let-p7-ijg-jg-weight-of-the-car-in-metric-tons-i-metric-ton-=-looo-kgthe-tractive-coefficient-ie-the-force-in-kg-required-to-move-oneton-at-a-steady-speed-on-the-leveland-s-the-slope-or-gradien-2CENHMY.jpg)
A text-book of electrical engineering;. 450 3-18.10* 14-6 20 490 3-46.106 21-3 25 505 3-56.106 Motor 27-3 la £ = 500 - 2-75 . 7„ r.p.m. = 3-18.106.1 5 486-2 970
![GF120B, Manomètres de force, 100 mm Face, Metric Scale, a utiliser avec Série RCH 13 tonnes | Enerpac GF120B, Manomètres de force, 100 mm Face, Metric Scale, a utiliser avec Série RCH 13 tonnes | Enerpac](https://www.enerpac.com/file/v1070640020577129210/general/EnerpacBoxRight.png)
GF120B, Manomètres de force, 100 mm Face, Metric Scale, a utiliser avec Série RCH 13 tonnes | Enerpac
![SOLVED:(a) Neglecting gravitational forces, what force would be required to accelerate a 1200-metric-ton spaceship from rest to one-tenth the speed of light in 3 days? In 2 months? (One metric ton =1000 SOLVED:(a) Neglecting gravitational forces, what force would be required to accelerate a 1200-metric-ton spaceship from rest to one-tenth the speed of light in 3 days? In 2 months? (One metric ton =1000](https://cdn.numerade.com/previews/5bdd9fad-6830-42e2-a090-067b411955f7_large.jpg)
SOLVED:(a) Neglecting gravitational forces, what force would be required to accelerate a 1200-metric-ton spaceship from rest to one-tenth the speed of light in 3 days? In 2 months? (One metric ton =1000
![SOLVED: 5. (a) Calculate the buoyant force on 15,000 metric tons (1 ton = 1000kg) of solid steel (density 7.8 x 103 kg / m3) completely submerged in water, and compare this SOLVED: 5. (a) Calculate the buoyant force on 15,000 metric tons (1 ton = 1000kg) of solid steel (density 7.8 x 103 kg / m3) completely submerged in water, and compare this](https://cdn.numerade.com/ask_previews/fdee20e4-b80c-456b-8f79-3c0df163e7c6_large.jpg)
SOLVED: 5. (a) Calculate the buoyant force on 15,000 metric tons (1 ton = 1000kg) of solid steel (density 7.8 x 103 kg / m3) completely submerged in water, and compare this
![A truck of mass 7 metric tonnes is moving with speed 36 km per hour .When brakes are applied it stops in - Brainly.in A truck of mass 7 metric tonnes is moving with speed 36 km per hour .When brakes are applied it stops in - Brainly.in](https://hi-static.z-dn.net/files/d2a/5a72d7a3875f4ac9fb707550b8d366a0.jpg)
A truck of mass 7 metric tonnes is moving with speed 36 km per hour .When brakes are applied it stops in - Brainly.in
A 10 metric ton drives up a hilly road of gradient 1 in 50 at a speed of 36 kmh^ 1. If the coefficient of kinetic friction between the road and tyresis
![A cart has mass 2 metric tone and sand of 1 metric tone is inside the cart. Now a force of 10 N is applied on cart and sand starts to leak A cart has mass 2 metric tone and sand of 1 metric tone is inside the cart. Now a force of 10 N is applied on cart and sand starts to leak](https://dwes9vv9u0550.cloudfront.net/images/6540127/30505815-0dbe-4cf3-ad45-9f230156d3a5.jpg)